• Thermodynamics 7th Edition Solutions
• Cengel Boles Thermodynamics 7th Edition Solution Manual Pdf

Chapter 1 - Section A - Mathcad Solutions 1.4 The equation that relates deg F to deg C is: t(F) = 1.8 t(C) + 32. Solve this equation by setting t(F) = t(C). T 0 Guess solution: Given t = 1.8t  32 1.5 By definition: P= 40 Find ( t) F Ans. F = mass˜ g A P  3000bar D  4mm F  P˜ A g 9.807 A m S 4 ˜D mass  2 s 1.6 By definition: P= F 2 F g Note: Pressures are in gauge pressure. A 12.566 mm mass 2 384.4 kg Ans. F = mass˜ g A P  3000atm D  0.17in F  P˜ A g 32.174 S 2 ˜D 4 F mass  g A ft 2 sec A mass 2 0.023 in 1000.7 lbm Ans. 1.7 Pabs = U ˜ g˜ h  Patm U  13.535˜ gm 3 g  9.832˜ 1.8 U  13.535˜ gm 3 Pabs  U ˜ g˜ h  Patm g  32.243˜ ft 2 Pabs 176.808 kPa Ans.

Thermodynamics 7th Edition Solutions

H  25.62in s cm Patm  29.86inHg h  56.38cm 2 s cm Patm  101.78kPa m Pabs  U ˜ g˜ h  Patm 1 Pabs 27.22 psia Ans. 1.10 Assume the following: U  13.5 gm g  9.8 3 1.11 2 s cm P  400bar m P h h U˜g Ans. 302.3 m The force on a spring is described by: F = Ks x where Ks is the spring constant. First calculate K based on the earth measurement then gMars based on spring measurement on Mars. On Earth: F = mass˜ g = K˜ x g  9.81 mass  0.40kg m x  1.08cm 2 s F  mass˜ g F Ks  3.924 N F x Ks 363.333 N m On Mars: x  0.40cm gMars  1.12 Given: FMars mass d P = U ˜ g dz FMars  K˜ x gMars 0.01 and: FMars mK U= 3 4 u 10 Ans.

Kg M˜ P R˜ T Substituting: P ´ Denver 1 Separating variables and integrating: µ dP = µ P ¶P sea § PDenver ln ¨ After integrating: © Psea ¹ Taking the exponential of both sides and rearranging: Psea  1atm M  29 2 mK = PDenver = Psea gm mol M˜ P d ˜g P=  R˜ T dz zDenver ´ µ µ ¶0 M˜ g R˜ T § M˜ g dz © R˜ T ¹ ¨ ˜ zDenver §  M˜ g ˜ z ¨ Denver R˜ T © ¹ ˜e g  9.8 m 2 s 3 R  82.06 cm ˜ atm M˜ g ˜ zDenver R˜ T PDenver  Psea zDenver  1˜ mi T  ( 10  273.15)K mol˜ K 0.194 §  M˜ g ˜ z ¨ Denver R˜ T ¹ ˜ e© PDenver 0.823 atm Ans. PDenver 0.834 bar Ans.

1.13 The same proportionality applies as in Pb. Gearth  32.186˜ ft gmoon  5.32˜ 2 1.14 gearth gmoon 'learth M  'learth˜ lbm M wmoon  M˜ gmoon wmoon costbulb  costbulb hr 5.00dollars ˜ 10 day 1000hr 18.262 D  1.25ft 113.498 dollars yr Ans. 113.498 lbm 18.767 lbf Ans.

Cengel Boles Thermodynamics 7th Edition Solution Manual Pdf

Hr 0.1dollars ˜ 70W ˜ 10 day kW˜ hr costelec  costtotal  costbulb  costelec 1.15 'lmoon  18.76 2 s s 'learth  'lmoon˜ ft costelec 25.567 dollars yr costtotal 43.829 dollars yr Ans. Mass  250lbm g  32.169 ft 2 s 3 (a) F  Patm˜ A  mass˜ g (c) 'l  1.7ft 1.18 2 Work  EK 1.19 Wdot = Ans. A 424.9 ft˜ lbf 2 S 2 ˜D 4 A 4 110.054 kPa 'EP  mass˜' g˜ l 'EP m s 1000 kJ Work 1000 kJ Ans. Mass˜' g˜ h ˜ 0.91˜ 0.92 time Wdot  200W g  9.8 m 2 s 4 m 2 s Work EK Ans. G  9.813 Work  F˜ 'l u  40 2 3 4.8691 u 10 ft˜ lbf Ans.

1.909 u 10 N F Pabs mass  1250kg mass˜ u 16.208 psia 'PE A 1.227 ft Ans. 'PE  mass˜' g˜ l F 1 3 mass  150kg 'l  0.83m EK  A Work (a) F  Patm˜ A  mass˜ g (c) 2 Work  F˜ 'l Patm  101.57kPa (b) Pabs  ˜D 2.8642 u 10 lbf Pabs D  0.47m 1.16 4 F F A (b) Pabs  S A Patm  30.12inHg 'h  50m 2 0.173 m Ans. 15.848 kJ Ans. 1.222 kJ Ans. Wdot mdot  1.22 a) costcoal  mdot g˜ 'h˜ 0.91˜ 0.92 0.488 25.00 ton 29˜ costgasoline  costcoal MJ 0.95 GJ kg s Ans.

1 kg 2.00 gal 37˜ GJ costgasoline 14.28 GJ 1 3 m costelectricity  0.1000 kW˜ hr costelectricity 27.778 GJ 1 b) The electrical energy can directly be converted to other forms of energy whereas the coal and gasoline would typically need to be converted to heat and then into some other form of energy before being useful. The obvious advantage of coal is that it is cheap if it is used as a heat source. Otherwise it is messy to handle and bulky for tranport and storage. Gasoline is an important transportation fuel. It is more convenient to transport and store than coal.

It can be used to generate electricity by burning it but the efficiency is limited. However, fuel cells are currently being developed which will allow for the conversion of gasoline to electricity by chemical means, a more efficient process.

Electricity has the most uses though it is expensive. It is easy to transport but expensive to store. As a transportation fuel it is clean but batteries to store it on-board have limited capacity and are heavy. 5 1.24 Use the Matcad genfit function to fit the data to Antoine's equation. The genfit function requires the first derivatives of the function with respect to the parameters being fitted.

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